Question

A car travels 22.0 m/s22.0 \mathrm{~m} / \mathrm{s} north for 30.0 min30.0 \mathrm{~min} and then reverses direction and travels 28.0 m/s28.0 \mathrm{~m} / \mathrm{s} for 15.0 min15.0 \mathrm{~min}. What is the car's total displacement? a) 1.44104 m1.44 \cdot 10^4 \mathrm{~m} b) 6.48104 m6.48 \cdot 10^4 \mathrm{~m} c) 3.96104 m3.96 \cdot 10^4 \mathrm{~m} d) 9.98104 m9.98 \cdot 10^4 \mathrm{~m}

Solution

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Answered 1 year ago
Answered 1 year ago
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The speed of a body can be described by the expression:

v=dt\begin{aligned} v &= \frac{d}{t} \end{aligned}

where dd is the displacement and tt is the time

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