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Question

A car travels $22.0 \mathrm{~m} / \mathrm{s}$ north for $30.0 \mathrm{~min}$ and then reverses direction and travels $28.0 \mathrm{~m} / \mathrm{s}$ for $15.0 \mathrm{~min}$. What is the car's total displacement? a) $1.44 \cdot 10^4 \mathrm{~m}$ b) $6.48 \cdot 10^4 \mathrm{~m}$ c) $3.96 \cdot 10^4 \mathrm{~m}$ d) $9.98 \cdot 10^4 \mathrm{~m}$

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 7The speed of a body can be described by the expression:

$\begin{aligned} v &= \frac{d}{t} \end{aligned}$

where $d$ is the displacement and $t$ is the time

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