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Question

A certain piece of news is being broadcast to a potential audience of 200,000 people. Let f(t) be the number of people who have heard the news after t hours. Suppose that y=f(t) satisfies

y=.07(200,000y),y(0)=10.y^{\prime}=.07(200,000-y), \quad y(0)=10 .

Describe this initial-value problem in words.

Solution

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Answered 2 years ago
Answered 2 years ago

Let f(t)f(t) satisfies the initial-value problem

y=.07(200,000y),y(0)=10,\begin{aligned} y'=.07(200,000-y), \quad y(0)=10, \end{aligned}

where f(t)f(t) represents the number of people who have heard the some news after tt hours. Those news were being broadcast to a potential audience of 200,000200,000 people.

We see that there are 1010 people at the beginning who have heard the news. We can calculate here y(0)y'(0) substituting y(0)y(0) into the equation, to get

y(0)=.07(200,00010)=13,999.3>0,\begin{aligned} y'(0)=.07(200,000-10)=13,999.3>0, \end{aligned}

so we conclude that the number of people who have heard the news after tt hours is proportional to the difference between the number of a potential audience, 200,000200,000, and that number y(t)y(t) and also that the obtained function is increasing.

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