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Question

A charge q of 10.0 C is placed somewhere in space. What is the work required to bring a charge of 1.0 mC from a point X, 10.0 m from q, to a point Y, 2.0 m from q? Does the answer depend on which path the charge follows?

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The work done in moving the charge from X\textbf{X} to Y\textbf{Y} can be calculated as follows

W=qΔV=q(VYVX)=q[kQryKQrx]W=q\Delta V=q(V_{Y}-V_{X})=q\left[ \frac{kQ}{r_{y}}-\frac{KQ}{r_{x}} \right]

where (q)(q) is the charge we would like to move, and (Q)(Q) is the (10(10 C)

W=KqQ[1ry1rx]=(8.99×109 Nm2/C2)×(1×103 C)×(10 C)[12 m110 m]\begin{align*} W&=KqQ\left[ \frac{1}{r_{y}}-\frac{1}{r_{x}} \right] \\ &=(8.99 \times 10^{9} \mathrm{~ N\cdot m^{2}/C^{2}})\times ( 1\times 10^{-3} \mathrm{~ C}) \times ( 10 \mathrm{~ C}) \left[ \frac{1}{2 \mathrm{~ m}}-\frac{1}{10 \mathrm{~ m}} \right] \end{align*}

W=3.6×107 JW=3.6 \times 10^{7} \mathrm{~ J}

The work done doesn't depend on the path followed by the charge.

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