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Question

# A circular ring has a cross-section as shown (left). If the outer radius is 22mm and the inner radius 20mm, calculate the cross-sectional area of the ring.

Solution

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The cross-sectional area of the ring $A$ is the difference between the area of the outer circle $ِA_1$ and the area of the inner circle $A_2$.

$A=A_1-A_2$

$A=\pi r_{1}^{2}-\pi r_{2}^{2}= \pi \left(r_{1}^{2}- r_{2}^{2}\right)$

Replace $r_{1}$ with $22$ and $r_{2}$ with $20$

$A= \pi \left(22^{2}- 20^{2}\right)=263.89378$

The cross-sectional area of the ring is about $\text{\color{#4257b2}$264$ mm$^2$}$

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