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Question

A cleaner pushes a 4.50-kg laundry cart in such a way that the net external force on it is 60.0 N. Calculate the magnitude of his cart's acceleration.

Solution

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a) From  Newton’s second law\textbf{ Newton's second law}we know that

Fext=ma\sum F_{ext} = ma

Where :

  • Fext\sum F_{ext} is the resultant external force that affect on the object.
  • aa are the mass and the acceleration of the object.

From givens Fext=60   \sum F_{ext} = 60\ \; N ,m=4.5m = 4.5 kg Hence

Fext=maa=Fextm=604.5=13.3333\begin{align*} \sum F_{ext} &= m a\\ a &= \dfrac{\sum F_{ext}}{m} \\ &=\dfrac{60}{4.5}\\ &=13.3333 \end{align*}

a=13.3333   m/s2\boxed{a = 13.3333 \ \; \mathrm{m/s^2}}

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