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# A cleaner pushes a 4.50-kg laundry cart in such a way that the net external force on it is 60.0 N. Calculate the magnitude of his cart's acceleration.

Solution

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a) From $\textbf{ Newton's second law}$we know that

$\sum F_{ext} = ma$

Where :

• $\sum F_{ext}$ is the resultant external force that affect on the object.
• $a$ are the mass and the acceleration of the object.

From givens $\sum F_{ext} = 60\ \;$ N ,$m = 4.5$ kg Hence

\begin{align*} \sum F_{ext} &= m a\\ a &= \dfrac{\sum F_{ext}}{m} \\ &=\dfrac{60}{4.5}\\ &=13.3333 \end{align*}

$\boxed{a = 13.3333 \ \; \mathrm{m/s^2}}$

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