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Question

A computer hard disk starts from rest, then speeds up with an angular acceleration of α=190rads2\alpha=190 \dfrac{\text{rad}}{\text{s}^2} until it reaches its final angular speed of ωf=7200 rpm\omega_f=7200~\text{rpm}. How many revolutions has the disk made t=10.0 st=10.0~\text{s} after it starts up?

Solution

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Answered 11 months ago
Answered 11 months ago
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Here we are given a final angular speed with the value of:

ωf=7200 rpm\omega_f=7200~\text{rpm}

Or in rs\dfrac{\text{r}}{\text{s}}:

ωf=7200 rpm160 s=120 rs\omega_f=7200~\text{rpm}\cdot\frac{1}{60~\text{s}}=120~\frac{\text{r}}{\text{s}}

The initial angular speed is zero because the hard disk was at the rest at the beginning:

ωi=0 rpm\omega_i=0~\text{rpm}

Angular acceleration is given as:

α=190 rads2\alpha=190~\frac{\text{rad}}{\text{s}^2}

If we know that:

1 rads=9.5493 rpm1~\frac{\text{rad}}{\text{s}}=9.5493~\text{rpm}

Then our angular acceleration expressed in rpms\dfrac{\text{rpm}}{\text{s}} is:

α=1909.5493 rpms=1814.37 rpms\alpha=190\cdot9.5493~\frac{\text{rpm}}{\text{s}}=1814.37~\frac{\text{rpm}}{\text{s}}

And now in rs2\dfrac{\text{r}}{\text{s}^2} where the previous number we willmultiply with 160 s\dfrac{1}{60~\text{s}}:

α=1814.37160 s rs=30.24 rs2\alpha=1814.37\cdot\dfrac{1}{60~\text{s}}~\frac{\text{r}}{\text{s}}=30.24~\frac{\text{r}}{\text{s}^2}

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