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A concave mirror has a radius of curvature of 26.0 cm. An object that is 2.4 cm tall is placed 30.0 cm from the mirror. a. Where is the image position? b. What is the image height?

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In this problem, we have a concave mirror, and we need to find the position of the image (part aa), and the height of the image (part bb). We are going to use two equations, the mirror equation 1f=1do+1di\frac{1}{f} = \frac{1}{d_{o}}+ \frac{1}{d_{i}} where ff is the focal length of mirror, dod_{o} is the position of our object, and did_{i} is the position of image. Also, we need to find the focal length of the mirror, and for that we use the equation f=r2f=\frac{r}{2} Furthermore, we are going to use the magnification equation to find the image height M=dido=hihoM= -\frac{d_{i}}{d_{o}}= \frac{h_{i}}{h_{o}}

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