Question

A crate is pulled by a force of $628 \mathrm{~N}$ across the floor by a worker using a rope making an angle of $46.0^{\circ}$ with the floor. How much work does the force on the rope do, if the crate is pulled $15.0 \mathrm{~m}$.

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 2Work done by force which is not in direction of motion to move body for distance s is expressed by equation:

$\begin{align*} W &= F \cdot \cos{\theta} \cdot s \tag{only horizontal component of force do the work}\\ &= 628\ \mathrm{N} \cdot \cos{46.0^{\circ}} \cdot 15.0\ \mathrm{m} \tag{Unit is joule: $N\cdot m = J$ }\\ &=\boxed{6540\ \mathrm{J}}\\ \end{align*}$

## Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## More related questions

1/4

1/7