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Question

A cube of side 4 cm is enlarged by a ratio of 3:1. a) What is the volume of: i) the original cube? ii) the enlarged cube? b) By what ratio has the volume been increased?

Solution

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Multiply the side length of the cube by the given ratio, the side length of the enlarged cube is:

31×4=12 cm\dfrac{3}{1} \times 4 = 12 \text{ cm}

a)\textbf{a)}

Since the volume of the cube is the cube of its side length, so:

  • The volume of the original cube is:

43=64 cm34^{3} = \boxed{\color{#c34632}{64 \text{ cm}^{3}}}

  • The volume of the enlarged cube is:

123=1728 cm312^{3} = \boxed{\color{#c34632}{1728 \text{ cm}^{3}}}

b)\textbf{b)}

Divide the volume of the enlarged cube by the volume of the original cube:

172864=271\dfrac{1728}{64} = \dfrac{27}{1}

So, the volume was enlarged by a ratio 27:1\boxed{\color{#c34632}{27 : 1}}

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