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Question

A cuboid measuring 3 cm by 5 cm by 2 cm is enlarged by a ratio of 2:1, a) What is the volume of: i) the original cuboid? ii) the enlarged cuboid? b) By what ratio has the volume been increased?

Solution

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Multiply the three dimensions of the cuboid by the given ratio, the dimensions of the enlarged cuboid are:

21×3=6 cm\dfrac{2}{1} \times 3 = 6 \text{ cm}

21×5=10 cm\dfrac{2}{1} \times 5 = 10 \text{ cm}

And,

21×2=4 cm\dfrac{2}{1} \times 2 = 4 \text{ cm}

a)\textbf{a)}

Since the volume of the cuboid is the production of its three dimensions, so:

  • The volume of the original cuboid is:

3×5×2=30 cm33 \times 5 \times 2 = \boxed{\color{#c34632}{30 \text{ cm}^{3}}}

  • The volume of the enlarged cuboid is:

6×10×4=240 cm36 \times 10 \times 4 = \boxed{\color{#c34632}{240 \text{ cm}^{3}}}

b)\textbf{b)}

Divide the volume of the enlarged cuboid by the volume of the original cuboid:

24030=81\dfrac{240}{30} = \dfrac{8}{1}

So, the volume was enlarged by a ratio 8:1\boxed{\color{#c34632}{8 : 1}}

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