Try the fastest way to create flashcards
Question

# A current of $4.82 \mathrm{~A}$ exists in a $12.4 \mathrm{\Omega}$ resistor for $4.60 \mathrm{~min}$. (a) How much charge and (b) how many electrons pass through any cross section of the resistor in this time?

Solution

Verified
Step 1
1 of 2

a)

From equation (29-1) we can find the total charge travelled trough the resistor in the given time:

\begin{align*} i &= \frac{d q}{d t} \\ d q &= i \cdot d t \\ \Delta q &= \int i \cdot d t \\ \Delta q &= i \cdot \Delta t = 4.82 \ \text{A} \cdot (4.6 \cdot 60) \ \text{s} \end{align*}

$\boxed{\Delta q = 1324.8 \ \text{C}}$

b)

To find the number of passed electrons we have to divide the total passed charge with the charge of a single electron $q = e$.

$\Delta N = \frac{\Delta q}{e} = \frac{1324.8 \ \text{C}}{1.602 \cdot 10^{-19} \ \text{C}}$

$\boxed{\Delta N \approx 8.269 \cdot 10^{21}}$

## Recommended textbook solutions #### Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

4th EditionISBN: 9780133942651 (8 more)Randall D. Knight
3,508 solutions #### Mathematical Methods in the Physical Sciences

3rd EditionISBN: 9780471198260 (1 more)Mary L. Boas
3,355 solutions #### Physics, Volume 2

5th EditionISBN: 9780471401940Halliday, Kenneth S. Krane, Resnick
902 solutions #### Fundamentals of Physics

10th EditionISBN: 9781118230718 (3 more)David Halliday, Jearl Walker, Robert Resnick
8,971 solutions