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Question

A deposit of 50 is made at the beginning of each month in an account that pays 8% interest. compounded monthly. The balance A in the account at the end of 5 years is given by

A=50(1+0.0812)1++50(1+0.0812)00A=50\left(1+\frac{0.08}{12}\right)^{1}+\cdots+50\left(1+\frac{0.08}{12}\right)^{00}. Find A.

Solution

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Answered 1 year ago
Answered 1 year ago
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To find AA, we have to use the formula for the sum of a finite geometric sequence:

a1,a1r,a1r2,...,a1rn1\begin{align*} a_1, a_1r, a_1r^2,...,a_1r^{n-1} \end{align*}

with common ration r1r\neq1 that is:

Sn=i=1na1ri1=a1(1rn1r)\begin{align*} S_n&=\displaystyle\sum_{i=1}^n a_1r^{i-1}=a_1\cdot \left( \frac{1-r^n}{1-r} \right) \end{align*}

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