Question

(a) Derive the given equation. (b) If the density increases by 1.50%1.50 \% from point 1 to point 2, what happens to the volume flow rate?

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A.\textbf{A.}

Deriving continuity equation for compressible fluids from incompressible fluids:

A1v1=A2v2\begin{align*} A_1v_1 = A_2 v_2 \end{align*}

We know that:

m=ρV\begin{align*} m &= \rho V \\ \end{align*}

and the total mass flow rate for steady flow condition is:

dMdt=0\begin{align*} \mathrm{\frac{dM}{dt}} &= 0 \end{align*}

Using the relation of mass flow rate to volume flow rate:

dMdt=ρdVdt\begin{align} \mathrm{\frac{dM}{dt}} &= \rho \mathrm{\frac{dV}{dt}} \end{align}

Solving for the mass in and out:

dm1dt=ρA1v1dm2dt=ρA2v2ρA1v1ρA2v2=0ρA1v1=ρA2v2\begin{align*} \mathrm{\frac{dm_1}{dt}} &= \rho A_1 v_1\\ \mathrm{\frac{dm_2}{dt}} &= \rho A_2 v_2\\ \Rightarrow & \rho A_1 v_1 - \rho A_2 v_2 = 0\\ \Rightarrow & \boxed{\rho A_1 v_1 = \rho A_2 v_2} \end{align*}

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