Question

A drama club plans to sell 100 tickets to a school musical. An adult ticket costs $6, and a student ticket costs$4. Students who attend the school get a $1 discount. The club expects two thirds of the student tickets to be discounted. Write an equation that gives the total revenue r (in dollars) as a function of the number a of adult tickets sold.

Solution

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Let aa be the number of adult ticket sold and rr the total revenue.

An adult ticket costs $6\$6. Therefore, revenue from adult tickets is $6a\color{Brown}\$6a.

Since drama club has 100100 tickets to sell, number of students tickets will be 100a100-a.

Student ticket costs $4\$4. Since students who attend the school get $1\$1 discount, their ticket costs $3\$3.

Two thirds of the student tickets will be discounted. Therefore, revenue from discounted student tickets will be

$323(100a)\color{Brown}\$3\cdot \dfrac{2}{3} \cdot (100-a)

$3\$3 is cost of the student ticket with discount, and 23(100a)\dfrac{2}{3}\cdot (100-a) is a number of students with discount.

Since wo thirds of the student tickets will be discounted, one third will not. (123=131-\frac{2}{3}={1}{3}) Therefore, revenue from discounted student tickets will be

$413(100a)\color{Brown}\$4\cdot \dfrac{1}{3} \cdot (100-a)

$4\$4 is cost of the student ticket without discount, and 13(100a)\dfrac{1}{3}\cdot (100-a) is a number of students without discount.

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