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Since the 1960s, the Free Expression Tunnel at North Carolina State University has been the University’s way to combat graffiti on campus. The tunnel is painted almost daily by various student groups to advertise club meetings, praise athletic accomplishments, and declare undying love. You and your engineering classmates decide to decorate the tunnel with chemical process flowcharts and key equations found in your favorite text, so you purchase a can of spray paint. The label indicates that the can holds nine fluid ounces, which should cover an area of approximately 25ft225 \mathrm{ft}^{2}. a) You measure the tunnel and find that it is roughly 8 feet wide, 12 feet high, and 148 feet long. Based on the stated coverage, how many cans of spray paint would it take to apply one coat to the walls and ceiling of the tunnel? b) Having just heard a lecture on process safety in your engineering class, you want to take appropriate safety precautions while painting the tunnel. One useful source for this type of information is the Safety Data Sheet (SDS), a document used in industry to provide workers and emergency personnel with procedures for safely handling or working with a specified chemical. Other sources of information about hazardous substances can be found in handbooks, and some countries, including the United States, have laws that require employers to provide their employees with Safety Data Sheets. Besides composition information, the SDS contains information such as physical properties (melting point, boiling point, flash point, etc.), other threats to health and safety, recommended protective equipment, and recommended procedures for storage, disposal, first aid, and spill handling. The SDS can typically be found online for most common substances. Search the web for “spray paint SDS” and find a representative SDS for a typical spray paint product. Based on the document you find, what are the top three hazards that you might encounter during your tunnel painting project? Suggest one safety precaution for each listed hazard.

Question

A drilling mud is a slurry pumped into oil wells being drilled. The mud has several functions: It floats rock cuttings to the top of the well where they can easily be removed; lubricates and cools the drill bit; and keeps loose solids and water from leaking into the borehole. A drilling mud is prepared by blending (SG = 4.37) with seawater (SG = 1.03). The seawater has a dissolved salt content of approximately 3.5 wt%. You have been asked to determine the specific gravity of the mud and the wt% barite. You collect a sample of the mud from a blending tank on an oil platform and make the following observations: (i) The mud appears homogeneous, even after standing for 2 days; (ii) the tare mass of the calibrated vessel into which you pour the sample of mud is 118 g; (iii) the volume of the collected sample is 100 mL, and the mass of the collection vessel and sample is 323 g; and (iv) the mass of the vessel and residue remaining after completely evaporating water from the sample is 254 g. a) Estimate the specific gravity of the mud and the wt% barite. b) What is the practical importance of Observation (i)?

Solution

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Given:

Objects: mud sample (contains salt, water and barite) and collection vessel

xsalt=msaltmsea=0.035x_{salt}=\dfrac{m_{salt}}{m_{sea}}=0.035

i) mud is homogeneous

ii) mvessel=118gm_{vessel}=118 g

iii) Vmud=100mLV_{mud}=100mL, mmud+mvessel=323gm_{mud} + m_{vessel}=323g

iv) mmud+mvesselmwater=254gm_{mud} + m_{vessel} - m_{water}=254g


a) Compute specific gravity of mud and weight percentage of barite\textit{a) Compute specific gravity of mud and weight percentage of barite}

b) Comment on i)\textit{b) Comment on i)}

a)

From iii), using ii):

Vmud=100mL,mmud=323g118g=205gρmud=mmudVmud=2.05kg/L\begin{equation*} V_{mud}=100mL, \quad m_{mud}=323g - 118g =205g \quad \Rightarrow \rho_{mud}=\dfrac{m_{mud}}{V_{mud}}=2.05 kg/L \end{equation*}

Specific gravity is relative density to some referent density, usually density of water at 4C4^{\circ}C - 1.00kg/L1.00kg/L

SGmud=2.05kg/L1kg/L=2.05\begin{equation*} \boxed{SG_{mud}=\dfrac{2.05 kg/L}{1kg/L}=2.05} \end{equation*}

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