## Related questions with answers

Question

A fair coin is tossed four times. What is the probability of obtaining. Exactly on e head?

Solution

VerifiedStep 1

1 of 2Let event of getting an head is a success then:

$p=\dfrac{1}{2}$

$q=1-\dfrac{1}{2}=\dfrac{1}{2}$

Evaluating probability of getting 1 head, using Bernoulli Trial:

$\begin{align*} _4C_1p^1q^{4-1}&=\dfrac{4!}{1!(4-1)!}\left(\dfrac{1}{2}\right)^1\left(\dfrac{1}{2}\right)^{4-1}\\ &=\dfrac{4!}{1!(3)!}\left(\dfrac{1}{2}\right)^1\left(\dfrac{1}{2}\right)^{3}\\ &=4 \times\left(\dfrac{1}{2^4}\right)\\ &=\dfrac{1}{4}\\ &=\textcolor{#4257b2}{0.25} \end{align*}$

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