## Related questions with answers

A family buys airline tickets online. Each ticket costs $167. The family buys travel insurance with each ticket that costs$19 per ticket. The Web site charges a fee of $16 for the entire purchase. The family is charged a total of$1132. How many tickets did the famiiy buy?

Solutions

VerifiedIf the number of tickets bought is $x$,the price of each ticket is $167\$$ and the travel insurance is $19\$$,so total cost per ticket is $x(167+19)$ and after removing the fee the family charged $1116\$$

$\begin{aligned}x(167+19)&=1132-16\\186x&=1116\\\text{[Divide both sides by 186]}\\x&=6\$\end{aligned}$

So,the number of tickets bought is $6$

We will let $t$ be the number of tickets the family buys. We will multiply the price of each ticket and the travel insurance to $t$. Then, we will come up with this equation $167t + 19t + 16 = 1132$. \par

$\begin{align*} 167t +19t + 16 &= 1132 \\ 186t + 16 - 16 &= 1132 -16 \\ 186t &= 1116 \\ \dfrac{186t}{186} &= \dfrac{1116}{186} \\ t &= 6 \end{align*}$

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