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(a) Find the voltage drop in an extension cord having a 0.0600Ω0.0600-\Omega resistance and through which 5.00 A is flowing. (b) A cheaper cord utilizes thinner wire and has a resistance of 0.300 Ω.0.300\ \Omega. What is the voltage drop in it when 5.00 A flows? (c) Why is the voltage to whatever appliance is being used reduced by this amount? What is the effect on the appliance?

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1 Concepts and Principles

Ohm’s Law\textbf{Ohm's Law}: The current II through a circuit element (other than a battery) can be determined by dividing the potential difference ΔV\Delta V across the circuit element by its resistance RR:

I=ΔVR\begin{gather*} I = \dfrac{\Delta V}{R} \tag{*} \end{gather*}

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