Question

A football player runs directly down the field for 35 m. He then turns right, at an angle of 2525^{\circ} from his original direction, and runs an additional 15 m before being tackled. What is his displacement from his original position? Given: Unknown:

Solution

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Answered 1 year ago
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The following are the given in the problem:

dx=35 mdy=15 mθ=25°\begin{align*} d_{x} &= 35 \text{ m} \\ d_{y} &= 15 \text{ m} \\ \theta &= 25 \degree \end{align*}

The problem wants us to determine the displacement of the football player from his original position after being tackled. This can be solve by applying the equation of magnitude of displacement as stated below:

d=Δx2+Δy2θ=tan1(ΔxΔy)\begin{align} d &= \sqrt{\Delta x^{2} + \Delta y^{2}}\\ \theta&=\tan^{-1}\left(\dfrac{\Delta x}{\Delta y}\right) \end{align}

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