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Question

(a) For a circuit, the parameters are RS=2kΩR_S=2 \mathrm{k} \Omega and RP=8kΩR_P=8 \mathrm{k} \Omega. (i) If the corner frequency is fL=50 Hzf_L=50 \mathrm{~Hz}, determine the value of CSC_S. (ii) Find the magnitude of the transfer function at f=20 Hz,50 Hzf=20 \mathrm{~Hz}, 50 \mathrm{~Hz}, and 100 Hz100 \mathrm{~Hz}. (b) Consider a circuit with parameters RS=4.7kΩR_S=4.7 \mathrm{k} \Omega, RP=25kΩR_P=25 \mathrm{k} \Omega, and CP=120pFC_P=120 \mathrm{pF}. (i) Determine the corner frequency fHf_H. (ii) Determine the magnitude of the transfer function at f=0.2fH,f=fHf=0.2 f_H, f=f_H, and f=8fHf=8 f_H.

Solution

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Answered 1 year ago
Answered 1 year ago
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Setup

In solving the problem, we recall the expressions for the open-circuit and short-circuit time constants as given in the textbook.

τS=(RS+RP)CS\tau_S = (R_S +R_P)C_S

τP=(RSRP)CP\tau_P= (R_S||R_P)C_P

We also recall the Laplace equivalent impedance expressions of each circuit component from the time domain to the complex frequency domain.

For resistors:

ZR=RZ_R = R

For capacitors:

ZC=1sCZ_C = \frac{1}{sC}

For inductors:

ZL=sLZ_L = sL

This will be essential in simplifying the analysis further in the next steps.

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