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A geneticist has studied the sequence of a gene in each of three species, A, B, and C. Species A and species B are sister species; species C is more distantly related. The geneticist has calculated the ratio of nonsynonymous (NS) to synonymous (S) nucleotide substitutions in the coding region of the gene in two ways—first, by comparing the gene sequences of species A and C, and second, by comparing the gene sequences of species B and C. The NS:S ratio for the comparison of species B and C is five times greater than it is for the comparison of species A and C. What might this difference in the NS:S ratios suggest?
Solutions
VerifiedGiven information, Species A and B are sister species whereas species C is distantly related. The NS:S ratio for the comparison of species B and C is five times greater than the comparison between A and C.
Based on the data, we can predict that positive selection has been operating, at least in one lineage to modify nucleotides in the gene.
The NS:S ratio suggests that the evolutionary rate of species B is higher compared with species A and C. This also depicts a positive selection on species B due to the high rates of nonsynonymous substitutions, which have a greater effect on a given organism.
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