A grindstone in the shape of a solid disk with diameter 0.520 m and a mass of 50.0 kg is rotating at 850 rev/min. You press an ax against the rim with a normal force of 160 N, and the grindstone comes to rest in 7.50 s. Find the coefficient of friction between the ax and the grindstone. You can ignore friction in the bearings.

Solution

Verified

Answered 11 months ago

Step 1

1 of 8

1 Concepts and Principles

1- $\textbf{Rotational Acceleration}$ $\alpha$ : The average rotational acceleration $\alpha$ (alpha) of a rotating rigid body (sometimes called angular acceleration) is its change in rotational velocity $\Delta \omega$ during a time interval $\Delta t$ divided by that time interval:

\begin{gather*} \alpha = \dfrac{\Delta \omega}{\Delta t} \tag{1} \end{gather*}

The unit for rotational acceleration is $\mathrm{(rad/s)/s}=rads/^2$ .

2- $\textbf{Kinetic Friction Force}$ : when an object slides along a surface, the components of the forces parallel to the surface that the surface exerts on the object are called kinetic friction forces. These forces oppose the motion of the object. The kinetic friction force depends on the surfaces themselves (on the coefficient of kinetic friction $\mu_k$ ) and relates to the magnitude of the normal force component $n$ of the total force that the surface exerts on the moving object as

\begin{gather*} f_{k}=\mu_k n \tag{2} \end{gather*}

3- $\textbf{Rigid Object Under a Net Torque}$ : If a rigid object free to rotate about a fixed axis has a net external torque acting on it, the object undergoes an angular acceleration $\alpha$ , where

\begin{gather*} \sum \tau_{\mathrm{ext}} = I \alpha \tag{3} \end{gather*}

This equation is the rotational analog to Newton's second law in the particle under a net force model.

4- The magnitude of the $\textbf{torque}$ associated with a force $\overrightarrow{\mathbf{F}}$ acting on an object at a distance $r$ from the rotation axis is:

\begin{gather*} \tau = r F \sin{\phi} = Fd \tag{4} \end{gather*}

where $\phi$ is the angle between the position vector of the point of application of the force and the force vector, and $d$ is the moment arm of the force, which is the perpendicular distance from the rotation axis to the line of action of the force.