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A helicopter is flying horizontally at 8.0 m/s and an altitude of 18 m when a package of emergency medical supplies is ejected horizontally backward with a speed of 12 m/s relative to the helicopter. Ignoring air resistance, what is the horizontal distance between the package and the helicopter when the package hits the ground?

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Given:

vxH=8msvxP(H)=12msvyiP=0msyiH=yiP=18myfP=0mxiH=xiP=0mg=9.81ms\begin{aligned} v_{x}^{H}&=8\,\rm{\frac{m}{s}}\\ v_{x}^{P(H)}&=-12\,\rm{\frac{m}{s}}\\ v_{yi}^{P}&=0\,\rm{\frac{m}{s}}\\ y_{i}^{H}=y_{i}^{P}&=18\,\rm{m}\\ y_{f}^{P}&=0\,\rm{m}\\ x_{i}^{H}=x_{i}^{P}&=0\,\rm{m}\\ g&=9.81\,\rm{\frac{m}{s}} \end{aligned}

In this problem we have to calculate the distance between the package and the helicopter.

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