## Related questions with answers

A hiker starts at his campsite and walks at 2 m/s northward for 30 min, then turns and walks due west at 1 m/s for 1 h. (a) Calculate the distance the hiker walks in 1.5 h. (b) Calculate the hiker's displacement from the campsite after walking for 1.5 h. (c) Explain the difference between distance and displacement.

Solution

Verified$\textbf{(a)}$\ When walking north, the hiker covers

$\begin{align*} v_{1}&=\dfrac{d_{1}}{t_{1}}\\ \rightarrow\quad d_{1}&=v_{1}t_{1}\\ &=2\ \frac{\text{m}}{\text{s}}\times 30\ \text{min}\cdot\dfrac{60\ \text{s}}{1\ \text{min}}\\ &=\ \quad\boxed{3600\ \text{m}} \end{align*}$

and when walking west

$\begin{align*} v_{2}&=\dfrac{d_{2}}{t_{2}}\\ \rightarrow\quad d_{2}&=v_{2}t_{2}\\ &=1\ \frac{\text{m}}{\text{s}}\times 1\ \text{h}\cdot\dfrac{3600\ \text{s}}{1\ \text{h}}\\ &=\ \quad\boxed{3600\ \text{m}} \end{align*}$

The total distance is the sum of these two distances

$\begin{align*} d&=d_{1}+d_{2}\\ &=3600\ \text{m}+3600\ \text{m}\\ &=\quad\boxed{7200\ \text{m}}\\ \end{align*}$

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