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How much charge is on each plate of a 4.00μF4.00-\mu \mathrm{F} capacitor when it is connected to a 12.0V12.0-\mathrm{V} battery?

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In this problem, a capacitor is connected to a battery. The battery is rated at ΔV=12.0 V\Delta V = 12.0~\mathrm{V}, and the capacitor has capacitance C=4.00 μF=4.00×106 FC = 4.00~\mathrm{\mu F} = 4.00 \times 10^{-6}~\mathrm{F}. We calculate the charge on the plate of the capacitor.

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