Question

A hydrogen atom is in its first excited state (n = 2). Calculate the total energy of the system.

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Finally, total energy of the system EE is the sum of it's kinetic and potential energy

E=K+UE=3.40eV6.80eVE=3.40eV.\begin{align*} E &= K + U \tag{inserting results (8) and (11)} \\ E &= 3.40 \: \mathrm{eV} - 6.80 \: \mathrm{eV} \\ E &= \boxed{ -3.40 \: \mathrm{eV} }. \tag{12} \end{align*}

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