## Related questions with answers

A hydrogen atom is in its first excited state (n = 2). Using the Bohr theory of the atom, calculate the angular momentum of the electron.

Solutions

VerifiedIn this problem, a hydrogen atom is excited to the first excited state, corresponding to $n = 2$. We use the Bohr model in this problem. For this part, we calculate the angular momentum of the electron.

Given values:

$n=2$

In part $\textbf{c)}$ we have to find the angular momentum of the electron.

For the state $n=2$ angular momentum $L_{n=2}$, yields:

$\begin{align} L_{n=2}=\frac{n\textrm{h}}{2\pi} \end{align}$

It follows:

$\begin{align*} L_{n=2}=\frac{2\left[6.63\times10^{-34}\textrm{J}\cdot{s}\right]}{2\pi} \end{align*}$

Solution is:

$\begin{align*} \boxed{L_{n=2}=2.11\times10^{-34}\textrm{J}\cdot{s}} \end{align*}$

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