## Related questions with answers

A jetliner, traveling northward, is landing with a speed of 69 m/s. Once the jet touches down, it has 750 m of runway in which to reduce its speed to 6.1 m/s. Compute the average acceleration (magnitude and direction) of the plane during landing.

Solutions

VerifiedThe plane's starting and the final velocity are:

$v_0=69\,\text{m/s}\\ v=6.1\,\text{m/s}$

and the distance is:

$x=750\,\text{m}$

We have to calculate the average acceleration of the plane.

To solve for the acceleration we will use the following equation

$v_f^2=v_o^2+2ax$

Plugging in the values we get:

$\begin{align*} 6.1^2&=69^2+2a750\\ 37.21&=4761+1500a\\\ -4723.79&=1500a\\\\ a&=\dfrac{-4723.79}{1500}\\\\ a&=\boxed{-3.1\text{ m/s}^2} \end{align*}$

Since acceleration is negative it means the plane is slowing down.

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