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A study suggests that airlines have increased restrictions on cheap fares by raising overnight requirements (The Wall Street Journal, August 19, 2008). This would force business travelers to pay more for their flights, since they tend to need the most flexibility and want to be home on weekends Eight months ago, the overnight stay requirements were as follows:

 One night  Two nights  Three  nights  Saturday  night 37%17%28%18%\begin{array}{|c|c|c|c|} \hline \text { One night } & \text { Two nights } & \begin{array}{c} \text { Three } \\ \text { nights } \end{array} & \begin{array}{c} \text { Saturday } \\ \text { night } \end{array} \\ \hline 37 \% & 17 \% & 28 \% & 18 \% \\ \hline \end{array}

A recent sample of 644644 flights found the following restrictions:

 One night  Two nights  Three  nights  Saturday  night 11713729892\begin{array}{|c|c|c|c|} \hline \text { One night } & \text { Two nights } & \begin{array}{c} \text { Three } \\ \text { nights } \end{array} & \begin{array}{c} \text { Saturday } \\ \text { night } \end{array} \\ \hline 117 & 137 & 298 & 92 \\ \hline \end{array}

a. Specify the competing hypotheses to test whether the proportions cited by the study have changed.

b. At a 5% significance level, what is the critical value?

c. Calculate the value of the test statistic.

d. What is the conclusion to the hypothesis test? Interpret your results.

Question

A local TV station claims that 60% of people support Candidate A, 30% support Candidate B, and 10% support Candidate C. A survey of 500 registered voters is taken. The accompanying table indicates how they are likely to vote.

 Candidate A  Candidate B  Candidate C 35012525\begin{array}{|c|c|c|} \hline \text { Candidate A } & \text { Candidate B } & \text { Candidate C } \\ \hline 350 & 125 & 25 \\ \hline \end{array}

a. Specify the competing hypotheses to test whether the TV station's claim can be rejected by the data.

b. Use the pp-value approach to test the hypothesis at a 1% significance level.

Solution

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a.)\bold{a.)} The null hypothesis states that

H0:The TV station’s claim coincides with the data.H_0:\text{The TV station's claim coincides with the data.}

so the alternative hypothesis will be the opposite.

HA:The TV station’s claim can be rejected by the data.H_A:\text{The TV station's claim can be rejected by the data.}

The predicted values is equal to the proportion multiplied to nn. So in Mathematical terms, the null hypotheses is

H0:p1=0.60,p2=0.30,p3=0.10H_0: p_1=0.60, p_2=0.30, p_3=0.10

and the Alternative hypotheses is

Ha:p10.60 or p20.30 or p30.10H_a: p_1\ne0.60 \text{ or } p_2\ne0.30 \text{ or } p_3\ne0.10

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