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Question
A man stands on a merry-go-round that is rotating at 2.5 rad/s. If the coefficient of static friction between the man's shoes and the merry-go-round is
how far from the axis of rotation can he stand without sliding?
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VerifiedSolution A
Solution B
Answered 2 years ago
Step 1
1 of 5Given:
- Angular velocity of a merry-go-round: ;
- Coefficient of static friction: ;
Required:
- Distance from the axis of rotation where man can stand without sliding.
Step 1
1 of 2
In order to calculate the radius , we will use Newton's second law of linear motion. Note that the only horizontal force acting on the person is friction (). It is also important to remark that since there is no tangential acceleration (the angular speed is constant), the total acceleration is equal to the centripetal acceleration , which can be calculated with the angular speed . Finally, we replace and in the equation and then we solve for .
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