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A metal bar with length LL, mass mm, and resistance RR is placed on frictionless metal rails that are inclined at an angle ϕ\phi above the horizontal. The rails have negligible resistance. A uniform magnetic field of magnitude BB is directed downward as shown in Fig. we saw earlier. The bar is released from rest and slides down the rails. After the terminal speed has been reached, at what rate is electrical energy being converted to thermal energy in the resistance of the bar?

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(d) We simply substitute for II form part (c) and RR into equation (4), so we get the rate at which the electrical energy is converted into thermal energy in the bar:

Pe=I2R=(mg tanϕLB)2 RPe=m2g2Rtan2ϕL2B2\begin{gathered} P_e = I^2 R = \left( \dfrac{mg\ \tan{\phi}}{LB}\right)^2\ R\\\\ \therefore \quad \large \boxed{P_e = \dfrac{m^2g^2R\tan^2{\phi}}{L^2 B^2}} \end{gathered}

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