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Question

A metal rod that is 30.0 cm long expands by 0.0650 cm when its temperature is raised from 0.0C0.0^{\circ} C to 100.0C100.0^{\circ} \mathrm{C}. A rod of a different metal and of the same length expands by 0.0350 cm for the same rise in temperature. A third rod, also 30.0 cm long, is made up of pieces of each of the above metals placed end to end and expands 0.0580 cm between 0.0C0.0^{\circ} C and 100.0C100.0^{\circ} \mathrm{C}. Find the length of each portion of the composite rod.

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Given

Metal One\text{\textcolor{#4257b2}{Metal One}}

lo=30×102ml_{o}= 30 \times 10^{-2} \,\,\mathrm{m} ,,,, δl=0.065×102m,,,,T1=0Co,,,,T2=100Co\delta l = 0.065 \times 10^{-2} \,\,\mathrm{m} ,,,, T_{1} = 0 \,\,\mathrm{C^{o}} ,,,, T_{2} = 100 \,\,\mathrm{C^{o}}

Metal Two\text{\textcolor{#c34632}{Metal Two}}

δT=0.035×102m,,,,lo=30×102m\delta T = 0.035 \times 10^{-2} \,\,\mathrm{m} ,,,, l_{o} = 30 \times 10^{-2} \,\,\mathrm{m}

Composite Rod

lo=30×102m,,,,δT=0.058×102ml_{o} = 30 \times 10^{-2} \,\,\mathrm{m} ,,,, \delta T = 0.058 \times 10^{-2} \,\,\mathrm{m}

Solution

For Metal One\text{\textcolor{#4257b2}{Metal One}}

δT=α×loδT\delta T = \alpha \times l_{o} \delta T

The missed parameter here is is α\alpha so by solving for α\alpha

α1=δllo×δT=0.065×102m30×102m[1000]=2.167×105(Co)1\begin{align*} \alpha_{1} & = \dfrac{\delta l}{l_{o} \times \delta T}\\ &= \dfrac{0.065 \times 10^{-2} \,\,\mathrm{m}}{30 \times 10^{-2} \,\,\mathrm{m} [100 - 0]}\\ &= 2.167 \times 10^{-5} \,\,\mathrm{(C^{o})^{-1}} \end{align*}

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