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A metal sphere of radius 15 cm has a net charge of 3.0×108C3.0 \times 10^{-8} C. What is the electric field at the sphere’s surface?

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Given:

  • Radius: r=15 cmr = 15 \mathrm{~cm};
  • Charge: q=3×108 Cq = 3 \times 10^{-8} \mathrm{~C};
  • Potential: V()=0V(\infty) = 0;
  • Potential: ΔV=500 V\Delta V = - 500 \mathrm{~V};

Required:

a) The electric field EE;

b) The potential VV;

c) The distance dd;

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