Related questions with answers
A monatomic ideal gas expands slowly to twice its original volume, doing 450 J of work in the process. Find the heat added to the gas and the change in internal energy of the gas if the process is (a) isothermal; (b) adiabatic; (c) isobaric.
Solution
VerifiedGiven
we are given a monatomic ideal gas that expands to twice its original volume which means with work done = 450 J. We are asked to calculate the heat added to the gas and the change in internal energy if the process be (a) Isothermal (b) Adiabatic (c) Isobaric
Known
We all know that for a gas doing a work by heat or even insulated, the first law of thermodynamics is applied in this case which relates the heat, the work done and the change in internal energy and would be used to calculate and in this case.
Solution
(a) For the isothermal process, the temperature is constant during the process which means the change in temperature = 0. As the change in internal energy depends directly on , we could obtain equals zero by
Now plug the values for and into equation (1) to get when the process is isothermal
For the isothermal process all heat goes to increase the work done. and
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