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Question

A musical cent is a unit in a logarithmic scale of relative pitch or intervals. One octave is equal to 1200 cents. The formula

n=1200(log2ab)n = 1200 \left( \log _ { 2 } \frac { a } { b } \right)

can be used to determine the difference in cents between two notes with frequencies a and b. Find the interval in cents when the frequency changes from 443 Hertz (Hz) to 415 Hz.

Solution

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Answered 2 years ago
Answered 2 years ago
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In order to find the difference in cents between two notes with frequency changes from 443443 Hertz to 415415 Hertz, we will use the following formula.

n=1200 log2(ab)=1200 log2(443415)=1200 log21.0675=1200log101.0675log102logan=logbnlogba\begin{aligned} n&=1200 \text{ log}_2 \bigg(\dfrac{a}{b} \bigg)\\ &=1200 \text{ log}_2 \bigg(\dfrac{443}{415} \bigg)\\ &=1200 \text{ log}_2 1.0675\\ &=1200\dfrac{\log_{10} 1.0675}{\log_{10} 2} \quad \longrightarrow \log_{a} n = \dfrac{\log_{b} n}{\log_{b} a} \end{aligned}

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