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A normally distributed random variable X has a mean of 90. Given that the probability P(X<85)0.16:\mathrm{P}(X<85) \approx 0.16 : a. find the proportion of scores between 90 and 95, i.e., find P(90 < X < 95) b. find an estimate of the standard deviation for the random variable X.

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Part a\textbf{Part a}

To solve this part of the exercise, we must remember that the graph of the probability density function for the normal distribution is symmetrical about x=μx = \mu.

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