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Question

A nucleus with mass number A=182A=182 and atomic number Z=74Z=74 loses two neutrons. What are the resulting (a) mass number, (b) atomic number, and ( c) neutron number?

Solution

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Answered 2 years ago
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Mass number, A=182A = 182.

Atomic number, Z=74Z = 74.

So the neutron number, N=AZ=18274=108N = A - Z = 182 - 74 = 108.

If two neutrons are lost then the neutron number becomes

N=1082=106N= 108 - 2 = 106.

The atomic number ZZ remains same because it represents the total number of protons.

Mass number is A=Z+N=74+106=180A = Z + N = 74 + 106 = 180.

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