Question

# A number cube labeled 1-6 is tossed. What is the theoretical probability of rolling an odd number?$\begin{array} { l } { \text { A } \frac { 1 } { 2 } } \\ { \text { B } \frac { 1 } { 3 } } \end{array}$$\begin{array} { l } { \text { C } \frac { 1 } { 4 } } \\ { \text { D } \frac { 2 } { 3 } } \end{array}$

Solution

Verified
Step 1
1 of 2

\begin{align*} &\text{All the six numbers have probability} = \frac{1}{6} \\ \\ &\text{Then, probability to get an odd number will be:} \\ \\ &=\text{probability to get 1 + probability to get 3 + probability to get 5.} \\ \\ &= \frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2} \end{align*}

So, choice (A) is correct.

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