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Question

A parallel-plate capacitor has capacitance C0=5.00pFC_0=5.00 \mathrm{pF} when there is air between the plates. The separation between the plates is 1.50 mm1.50 \mathrm{~mm}. (a)(a) What is the maximum magnitude of charge QQ that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00×104 V/m3.00 \times 10^4 \mathrm{~V} / \mathrm{m} ? (b)(b) A dielectric with K=2.70K=2.70 is inserted between the plates of the capacitor, completely filling the volume between the plates. Now what is the maximum magnitude of charge on each plate if the electric field between the plates is not to exceed 3.00×104 V/m3.00 \times 10^4 \mathrm{~V} / \mathrm{m} ?

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C=QVab=ϵ0Ad      ,Vab=Ed     ,E=Qϵ0A\bf \color{#4257b2} {C=\dfrac{Q}{V_{ab}}=\epsilon_{0}\dfrac{A}{d} \ \ \ \ \ \ , V_{ab}=Ed \ \ \ \ \ , E=\dfrac{Q}{\epsilon_{0}A}}

K=CC0\bf \color{#c34632} {K=\dfrac{C}{C_{0}} \rightarrow}

(K is the dielctric constant, C nod is capcitance in air)

(C represent the capacitance, V is the potential difference between the plates, A is the area of the capacitor, d is the distance between plates, E is the electric field between plates)

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