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A particle moves 3.0 m along a circle of radius 1.5 m. (a) Through what angle does it rotate? (b) If the particle makes this trip in 1.0 s at a constant speed, what is its angular velocity? (c) What is its acceleration?
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First, we can calculate the covered angle with the covered distance and the perimeter (which can be calculated with the radius ). Once we have obtained , we proceed to calculate the angular speed . Note that and are equal to and respectively, because the rotation occurs at constant speed. Also, notice that there is no tangential acceleration because the angular speed is constant, and therefore the angular acceleration is zero. Finally, the total acceleration is equal to the centripetal acceleration , which can be calculated with and .
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