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A particle moves in a circle of radius aa at constant speed vv. Find the angular speed and the magnitude of the acceleration.

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Given that r(t)\textbf{r}(t) is that position vector of a moving object, then the speed of the particle will be given as the magnitude of the derivative of the position vector v(t)=r(t)v(t)=||\textbf{r}'(t)||. Then, v=kv=k, where kk is a constant.

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