A physics instructor wants to produce a double-slit interference pattern large enough for her class to see. For the size of the room, she decides that the distance between successive bright fringes on the screen should be at least 2.50 cm2.50 \mathrm{~cm}. If the slits have a separation d=0.0220 mmd=0.0220 \mathrm{~mm}, what is the minimum distance from the slits to the screen when 632.8 nm632.8 \mathrm{~nm} light from a HeNe\mathrm{He}-\mathrm{Ne} laser is used?


Answered 1 year ago
Answered 1 year ago
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In this problem, we are asked to calculate the distance between the slits and the screen in a two-slit interference pattern when a He-Ne laser light is used. The known values are given as follows:

y=2.50 cm0.0250 md=0.0220 mm0.0220103 mλ=632.8 nm632.8109 m\begin{aligned} y & = 2.50\text{ cm} \approx 0.0250\text{ m}\\ d & = 0.0220\text{ mm} \approx 0.0220 \cdot 10^{-3}\text{ m} \\ \lambda & = 632.8\text{ nm} \approx 632.8 \cdot 10^{-9}\text{ m} \end{aligned}

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