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Question

A plane leaves London for Boston, a distance of 5200 km, at 0945. The plane travels at an average speed of 800 km/h. If Boston time is five hours behind British time, what is the time in Boston when the aircraft lands?

Solution

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Apply the velocity law:

Time=distancespeed\text{Time} = \dfrac{\text{distance}}{\text{speed}}

=5200800=612 hours= \dfrac{5200}{800} = 6\dfrac{1}{2} \text{ hours}

Convert the part of hour to minutes:

12 hours=12×60=30 minutes\dfrac{1}{2} \text{ hours} = \dfrac{1}{2} \times 60 = 30 \text{ minutes}

So, the journey time is 6 hours and 30 minutes

If the plan takes off at 09:45, then it will land at

09:45+06:30=16:1509:45 + 06:30 = 16:15

Since Boston time is 5 hours behind British time, so the landing time is

16:1505:00=11:15 Boston time16:15 - 05:00 = \boxed{\color{#c34632}{11:15 \text{ Boston time}}}

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