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# A plane leaves London for Boston, a distance of 5200 km, at 0945. The plane travels at an average speed of 800 km/h. If Boston time is five hours behind British time, what is the time in Boston when the aircraft lands?

Solution

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Apply the velocity law:

$\text{Time} = \dfrac{\text{distance}}{\text{speed}}$

$= \dfrac{5200}{800} = 6\dfrac{1}{2} \text{ hours}$

Convert the part of hour to minutes:

$\dfrac{1}{2} \text{ hours} = \dfrac{1}{2} \times 60 = 30 \text{ minutes}$

So, the journey time is 6 hours and 30 minutes

If the plan takes off at 09:45, then it will land at

$09:45 + 06:30 = 16:15$

Since Boston time is 5 hours behind British time, so the landing time is

$16:15 - 05:00 = \boxed{\color{#c34632}{11:15 \text{ Boston time}}}$

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