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A plate having a thickness of 4.0 mm4.0 \mathrm{~mm} has an internal heat generation of 200MW/m3200 \mathrm{MW} / \mathrm{m}^3 and a thermal conductivity of 25 W/mC25 \mathrm{~W} / \mathrm{m} \cdot{ }^{\circ} \mathrm{C}. One side of the plate is insulated and the other side is maintained at 100C100^{\circ} \mathrm{C}. Calculate the maximum temperature in the plate.

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Answered 2 years ago
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Data given:

  • Thickness of a plate: x=4 cmx=4\text{ cm};
  • Heat generated per unit volume: q˙=200  W m3\dot{q}=200~\frac{\text{ W}}{\text{ m}^3};
  • One side of plate is isolated;
  • Temperature of the other side of plate: T=100 °CT=100\text{ \degree C};
  • Thermal conductivity: k=25  W m °Ck=25~\frac{\text{ W}}{\text{ m}\text{ \degree C}}.

Required:

  • Maximum temperature needs to be calculated.

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