## Related questions with answers

A population consists of these values: 2, 3, 6, 8, 11, 18.

Solution

VerifiedAdd the samples of size $n=2$ to obtain mean $\bar x$

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$\begin{aligned} \frac {2 + 3} {2}&= \frac{5}{2} =2.5 \\ \\ \frac {2 + 6} {2}&= \frac{8}{2} = 4.0 \\ \\ \frac {2 + 8} {2}&= \frac{10}{2} =5.0 \\ \\ \frac {2 + 11} {2}&= \frac{13}{2} = 6.5\\ \\ \frac {2 + 18} {2}&= \frac{20}{2} =10.0 \\ \\ \frac {3 + 6} {2}&= \frac{9}{2} =4.5 \\ \\ \frac {3 + 8} {2}&= \frac{11}{2} = 5.5\\ \\ \frac {3 + 11} {2}&= \frac{14}{2} = 7.0\\ \\ \frac {3+18} {2}&= \frac{21}{2} =10.5\\ \\ \frac {6 + 8} {2}&= \frac{14}{2} = 7.0 \\ \\ \frac {6 + 11} {2}&= \frac{17}{2} = 8.5 \\ \\ \frac {6 +18} {2}&= \frac{24}{2} = 12.0 \\ \\ \frac {8 +11} {2}&= \frac{19}{2} = 9.5 \\ \\ \frac {8 +18} {2}&= \frac{26}{2} = 13.0 \\ \\ \frac {11 + 18} {2}&= \frac{29}{2} = 14.5\\ \\ \end{aligned}$

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