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Question

A population has a mean μ\mu and a standard deviation σ\sigma. Find the mean and standard deviation of the sampling distribution of sample means with sample size n. μ=45,σ=15,n=100\mu=45, \sigma=15, n=100

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Answered 10 months ago
Answered 10 months ago
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Given:

μ=Mean=45σ=Standard deviation=15n=Sample size=100\begin{align*} \mu&=\text{Mean}=45 \\ \sigma&=\text{Standard deviation}=15 \\ n&=\text{Sample size}=100 \end{align*}

The mean\textbf{mean} of the sampling distribution of the sample mean is equal to the population mean:

μx=μ=45\mu_{\overline{x}}=\mu=45

The standard deviation\textbf{standard deviation} of the sampling distribution of the sample mean is equal to the population standard deviation divided by the square root of the sample size:

σx=σn=15100=1510=1.5\sigma_{\overline{x}}=\dfrac{\sigma}{\sqrt{n}}=\dfrac{15}{\sqrt{100}}=\dfrac{15}{10}=1.5

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