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Question
A proton in a linear accelerator has a de Broglie wavelength of 122 pm. What is the speed of the proton?
Solution
VerifiedAnswered 1 year ago
Answered 1 year ago
Step 1
1 of 2Using the de Broglie equation, which is: Where:
= wavelength
h= Planck's constant which is 6.626 J s
m= mass of the object
v= velocity or the speed of the object
Given the wavelength which is 122 pm or 122 meters sine pico(p) is equal to . The mass of a single proton is 1.67 kg. Thus finding the velocity our equation should be, $v= \dfrac{6.626\times10^{-34}\text{ J s}}{(1.67\times10^{-27} \text{ kg})(122\times10^{-12}\text{ m})}$
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