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Question

A “pseudo-Brayton cycle” consists of two isothermal processes in place of the two adiabatic processes in a Brayton cycle. Find the efficiency of a pseudo-Brayton heat engine.

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Known data: Useful work per cycle: W=175JW=175\:\mathrm{J} Adiabatic process coefficient: γ1=1.67\gamma_1=1.67 Adiabatic process coefficient: γ2=1.28\gamma_2=1.28 Output heat: Qout=65JQ_{out}=65\:\mathrm{J}

Required data: Pressure ratio, pHpL\frac{p_H}{p_L}

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