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Question

A random sample of the weekly supermarket bills for a number of families was observed and recorded in the table given. a. Find the mean bill and the standard deviation of the bills.b. Find unbiased estimates of the mean and variance of the population from which the data was taken.

Bill($)No. of families70-79.992780-89.993290-99.9948100-109.9925110-119.9937120-129.9921130-139.9918140-149.997\begin{matrix} Bill (\$) & \text{No. of families}\\ \text{70-79.99} & \text{27}\\ \text{80-89.99} & \text{32}\\ \text{90-99.99} & \text{48}\\ \text{100-109.99} & \text{25}\\ \text{110-119.99} & \text{37}\\ \text{120-129.99} & \text{21}\\ \text{130-139.99} & \text{18}\\ \text{140-149.99} & \text{7}\\ \end{matrix}

Solution

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Answered 2 years ago
Answered 2 years ago
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(a)\textbf{(a)} We know that the formula for mean xˉ\bar{x} with score value xix_i, corresponding frequency fif_i and total number of items nn is,

xˉ=i=1nxifii=1nfi\bar{x}=\dfrac{\sum_{i=1}^n x_i\cdot f_i}{\sum_{i=1}^n f_i}

Also, remember that if data is given in form of classes or groups then the score value will be average of each class.

For the given data we could calculate the mean of the sample using the above formula as follow.

xˉ=74.995(27)+84.995(32)+94.995(48)+104.995(25)+114.995(37)+124.995(21)+134.995(18)+144.995(7)27+32+48+25+37+21+18+7xˉ=22253.925215xˉ=103.506627907xˉ103.5\begin{align*} \bar{x} &= \dfrac{74.995(27)+84.995(32)+94.995(48)+104.995(25)+114.995(37)+124.995(21)+134.995(18)+144.995(7)}{27+32+48+25+37+21+18+7}\\\\ \bar{x} &= \dfrac{22253.925}{215}\\\\ \bar{x} &= 103.506627907\\\\ \bar{x} &\approx 103.5 \end{align*}

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