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A rectangular box without a top (a topless box) is to be made from 12 ft2\mathrm { ft } ^ { 2 } of cardboard. Find the maximum volume of such a box.

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The thing we want to maximize is the volume, hence our function to be maximized is f(x,y,z)=xyzf(x,y,z)=xyz, such that xx , yy and zz are the box dims.

And the constraint we have is the lateral area plus the base area is restricted to be 12 ft2^2, hence 2(xz+yz)+xy=122(xz+yz)+xy=12, such that the base dims are xx and yy.

Hence our problem is to maximize f(x,y,z)f(x,y,z) under the constraint g(x,y,z)g(x,y,z)

f(x,y,z)=xyz;g(x,y,z)=2(xz+yz)+xy12=0f(x,y,z)=xyz;\qquad{g(x,y,z)=2(xz+yz)+xy-12=0}

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